Question
In a Van de Graaff type generator a spherical metal shell is to be a $15 \times 10^6V$ electrode. The dielectric strength of the gas surrounding the electrode is $5 \times 10^7Vm^{–1.}$ What is the minimum radius of the spherical shell required? $($You will learn from this exercise why one cannot build an electrostatic generator using a very small shell which requires a small charge to acquire a high potential.$)$

Answer

Potential difference, $V = 15 \times 10^6V$
otelectrtc strength of the surrounding gas $={5}\times{10}^{7}\frac{\text{V}}{\text{m}}$
Electric field intensity, $E =$ Dielectric strength $= {5}\times {10}^{7}\frac{\text{V}}{\text{m}}$
Minimum radius of the spherical shell required for the purpose is given by,
$\text{r}=\frac{\text{V}}{\text{E}}$
$=\frac{15\times10^{6}}{5\times{10}^{7}}={0.3}\text{m}={30}\text{ cm}$
Hence, the minimum radius of the spherical shell required is $30\ cm.$

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