In a vernier callipers, each cm on the main scale is divided into… - Vidyadip

MCQ

In a vernier callipers, each $cm$ on the main scale is divided into $20$ equal parts. If tenth vernier scale division coincides with nineth main scale division. Then the value of vernier constant will be $\dots \; \times 10^{-2} \;mm$

A
$3$
✓
$5$
C
$7$
D
$9$

✓

Answer

Correct option: B.

$5$

b
$20 \; MSD =1 \; cm$

$1 \; MSD =\frac{1}{20} \; cm$

$10 \; VSD =9 \; MSD$

$1 \; VSD =\frac{9}{10} \; MSD$

$=\frac{9}{10} \times \frac{1}{20} \; cm$

$1 VSD =\frac{9}{200} \; cm$

VC $=1 MSD -1 \; VSD$

$=\frac{1}{20} \; cm -\frac{9}{200} \; cm$

$=\frac{1}{200} \times 10 \; mm$

VC $=5 \times 10^{-2} \; mm$

Ans. $5$

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