MCQ
In acidic medium, equivalent weight of ${K_2}C{r_2}{O_7}$ $(mol.\,\,wt.\, = M)$ is
- A$M/3$
- B$M/4$
- ✓$M/6$
- D$M/2$
${\text{Equivalent}}\,\,{\text{weight}}\,\,{\text{of }}{K_2}C{r_2}{O_7}$
$ = \frac{{{\text{Molecular}}\,\,{\text{Mass}}}}{6}$$ = \frac{{294.2}}{6} = \frac{M}{6}$.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$\begin{array}{*{20}{c}}
{C{H_3} - C \equiv C - C{H_2} - \mathop C\limits_{\mathop {||}\limits_O } - Cl}
\end{array} \ \xrightarrow[{BaS{O_4}}]{{{H_2} - Pd}}$