MCQ
In $AM$ , the centpercent modulation is achieved when
- ✓Carrier amplitude $=$ signal amplitude
- BCarrier amplitude $\neq$ signal amplitude
- CCarrier frequency $=$ signal frequency
- DCarrier frequency $\neq$ signal frequency
✓
Answer
Correct option: A.
Carrier amplitude $=$ signal amplitude
a
(a) When signal amplitude is equal to the carrier amplitude, the amplitude of carrier wave varies between $2A$ and zero.
${m_a} = \frac{{{\rm{Amplitude \,charge\, of\, carrier}}}}{{{\rm{Amplitude\, of \,normal \,carrier}}}} = \frac{{2A - A}}{A} \times 100 = 100\% $
(a) When signal amplitude is equal to the carrier amplitude, the amplitude of carrier wave varies between $2A$ and zero.
${m_a} = \frac{{{\rm{Amplitude \,charge\, of\, carrier}}}}{{{\rm{Amplitude\, of \,normal \,carrier}}}} = \frac{{2A - A}}{A} \times 100 = 100\% $
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Monochromatic light is refracted from air into the glass of refractive index μ. The ratio of the wavelength of incident and refracted waves is
Power factor is maximum in an $LCR$ circuit when
→Electromagnetic waves are transverse in nature is evident by.
A transformer has $100$ turns in the primary coil and carries $8 \,A$ current. If input power is one kilowatt, the number of turns required in the secondary coil to have $500\,V$ output will be
→As a result of interference of two coherent sources of light, energy is
If a charged particle kept at rest experiences an electromagnetic force:
A slit of width $a$ is illuminated by white light. For red light ($\lambda = 6500 \;\mathring A$), the first minima is obtained at $\theta = {30^o}$. Then the value of $a$ will be
→Two positive point charges of 12 μC and 8 μC are 10cm apart. The work done in bringing them 4 cm closer is
If $L $ is the coherence length and $c$ the velocity of light, the coherent time is
→The decay constant of a radio active substance is $0.173\, (years)^{-1}.$ Therefore :
→