In an experiment, electrons are accelerated, from rest, by applying, a voltage of $500 \,V.$ Calculate the radius of the path if a magnetic field $100\,mT$ is then applied. [Charge of the electron $= 1.6 \times 10^{-19}\,C$ Mass of the electron $= 9.1 \times 10^{-31}\,kg$ ]
A$7.5\times 10^{-3}\,m$
B$7.5\times 10^{-2}\,m$
C$7.5\,m$
D$7.5\times 10^{-4}\,m$
JEE MAIN 2019, Medium
Download our app for free and get started
D$7.5\times 10^{-4}\,m$
d ${{\text{k}}_{\text{e}}} = \frac{{{{\text{p}}^2}}}{{2{{\text{M}}_{\text{e}}}}} = 500\,{\text{e}} \ldots ({\text{i}})$
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
A square loop of edge length $2 \mathrm{~m}$ carrying current of $2 \mathrm{~A}$ is placed with its edges parallel to the $\mathrm{x}-\mathrm{y}$ axis. A magnetic field is passing through the $x-y$ plane and expressed as $\vec{B}=B_0(1+4 x) \hat{k}$, where $\mathrm{B}_0=5 \mathrm{~T}$. The net magnetic force experienced by the loop is. . . . . . . $\mathrm{N}$.
Two very long straight parallel wires, parallel to $y-$ axis,carrycurrents $4I$ and $I,$ along $+y$ directionand$-y$ direction, respectively. The wires are passes through the $x-$axis at the points $(d, 0, 0)$ and $(- d, 0, 0)$ respectively.The graph of magnetic field $z-$component as one moves along the $x-$axis from $x=- d$ to $x= +d,$ is best given by
An electron moves along vertical line and away from the observer, then pattern of concentric circular magnetic field lines which are produced due to its motion
An $\alpha -$ particle of $1\,MeV$ energy moves on circular path in uniform magnetic field. Then kinetic energy of proton in same magnetic field for circular path of double radius is......$MeV$
In the hydrogen atom, the electron is making $6.6 \times {10^{15}}\,r.p.s.$ If the radius of the orbit is $0.53 \times {10^{ - 10}}\,metre,$ then magnetic field produced at the centre of the orbit is......$Tesla$
A circular coil of $20$ $turns$ and radius $10\, cm$ is placed in uniform magnetic field of $0.10\, T$ normal to the plane of the coil. If the current in coil is $5\, A$, then the torque acting on the coil will be...... $Nm$
A charged particle of mass $m$ and charge $q$ describes circular motion of radius $r$ in a uniform magnetic field of strength $B$. The frequency of revolution is
The magnetic field on the axis of a circular loop of radius $100\,cm$ carrying current $I=\sqrt{2}\,A$, at point $1\,m$ away from the centre of the loop is given by
A long straight wire of radius a carries a steady current I. The current is uniformly distributed across its cross section. The ratio of the magnetic field at $\frac{a}{2}$ and $2$a from axis of the wire is: