In an experiment of single slit diffraction pattern, first minimu… - Vidyadip

MCQ

In an experiment of single slit diffraction pattern, first minimum for red light coincides with first maximum of some other wavelength . If wavelength of red light is $6600\,\mathop A\limits^o$ , then wavelength of first maximum will be.....$\mathop A\limits^o $

A
$3300$
✓
$4400$
C
$5500$
D
$6600$

✓

Answer

Correct option: B.

$4400$

b
In a single slit experiment, For diffraction maxima,

$a\sin \theta = \left( {2n + 1\frac{\lambda }{2}} \right)$

and for diffraction minima,

$a \sin \theta=n \lambda$

According to question,

$\left(2 \times 1+1 \frac{\lambda}{2}\right)=1 \times 6600$

$\left( {\because {\lambda _{\text{R}}} = 6600\,\,\mathop {\text{A}}\limits^o } \right)$

${\lambda = \frac{{6600 \times 2}}{3}}$

$\,\lambda = 4400\,\mathop {\text{A}}\limits^o $

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