MCQ
In an experiment, the values of refractive indices of glass were found to be $1.54, 1.53,$$1.44,1.54,1.56$ and $1.45$ in successive measurements, then Mean absolute error is
- A$0.004$
- ✓$0.04$
- C$0.4$
- D$4$
$\,\therefore \,\bar n = 1.51$
$\Delta n_1 = 1.51 - 1.54 = -0.03,$
$\Delta n_2 = 1.51 - 1.53 = -0.02,$
$\Delta n_3 = 1.51 - 1.44 = +0.07$
$\Delta n_4 = 1.51 - 1.54 = -0.03,$
$\Delta n_5 = 1.51 - 1.56 = -0.05,$
$\Delta n_6 = 1.51 - 1.45 = +0.06$
$\Delta \bar n = \frac{{\left| {\,\Delta {{\text{n}}_{\text{1}}}\,} \right|{\text{ }} + \left| {\,\Delta {{\text{n}}_{{\text{2}}\,}}} \right| + .... + \left| {\,\Delta {{\text{n}}_{{\text{6}}\,}}} \right|}}{6}$
$\, = \,\,\frac{{\left| {\, - 0.03\,} \right|{\text{ }} + \left| {\, - 0.02\,} \right| + \left| {\,0.07\,} \right| + \left| {\, - 0.03\,} \right| + \left| {\, - 0.05\,} \right| + \left| {\,0.06\,} \right|}}{6}\,$
$ = \,\frac{{0.26}}{6}\, = \,0.043\,\, \approx \,0.04\,\,\,\therefore \,\,\Delta \bar n\, = \,0.04$
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Statement$-I:$ Acceleration due to gravity is different at different places on the surface of earth.
Statement$-II:$ Acceleration due to gravity increases as we go down below the earth's surface.
In the light of the above statements, choose the correct answer from the options given below