In an experiment to study the relation between the potential diff… - Vidyadip

Question

In an experiment to study the relation between the potential difference across a resistor and the current through it, a student recorded the following observations:

Potential V (volts)	1.0	2.2	3.0	4.0	6.4
Current I (ampere)	0.1	0.2	0.6	0.4	0.6

On examining the above observations the teacher asked the student to reject one set of readings as the values were out of agreement with the rest. Which one of the above sets of readings can be rejected? Calculate the mean value of resistance of the resistor based on the remaining four sets of readings.

✓

Answer

Reading to be rejected in the table is (3.0, 0.6)

$R_{1} = \frac{1.0 \text{ V}}{0.1 \text{ A}} = \text{10 }\Omega \text{ ; }$

$ R_{2} = \frac{2.2 \text{ V}}{0.2 \text{ A}} = \text{11 }\Omega \text{ ; }$

$R_{3} = \frac{4.0 \text{ V}}{0.4 \text{ A}} = \text{ 10 } \Omega \text{ ; }$

$R_{4} = \frac{6.4 \text{ V}}{0.6 \text{ A}} = \text{10.6 } \Omega$

$\therefore \text{Mean } R = \text{(10 + 11 + 10 +10.6) } \Omega$

$ = \text{10.4 } \Omega$

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