MCQ
In an experiment with sonometer a tuning fork of frequency $256 Hz$ resonates with a length of $25 cm$ and another tuning fork resonates with a length of $16 cm$. Tension of the string remaining constant the frequency of the second tuning fork is ....  $Hz$
  • A
    $163.84$
  • $400$
  • C
    $320$
  • D
    $204.8$

Answer

Correct option: B.
$400$
b
(b) In case of sonometer frequency is given by

$n = \frac{p}{{2l}}\sqrt {\frac{T}{m}} $

==> $\frac{{{n_2}}}{{{n_1}}} = \frac{{{l_1}}}{{{l_2}}} \Rightarrow {n_2} = \frac{{25}}{{16}} \times 256 = 400\,\,\,Hz$

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