MCQ
In an isosceles triangle $ABC ,$ if $AC = BC$ and $AB ^2=2 AC ^2$ then $\angle C =$ ?
  • A
    $30^{\circ}$
  • B
    $45^{\circ}$
  • C
    $60^{\circ}$
  • $90^{\circ}$

Answer

Correct option: D.
$90^{\circ}$
Given, $AB ^2=2 AC ^2$
$\Rightarrow AB^2=AC^2+AC^2 .$
$\Rightarrow AB^2=AC^2+BC^2 .(\because AC=BC)$
$\therefore$ By the converse of Pythagoras theorem, we have $\angle C =90^{\circ}$.

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