In an organ pipe whose one end is at x = 0, the pressure is expressed by p = {p

Q: In an organ pipe whose one end is at $x = 0$, the pressure is expressed by $p = {p_0}\cos \frac{{3\pi x}}{2} \,\,sin\,\, 300\pi t$ where $x$ is in meter and $t$ in $sec$. The organ pipe can be

c Pressure is maximum at closed end and minimum at open end. At $x=0 m, \cos \frac{3 \pi x}{2}=\cos \frac{3 \pi \times 0}{2}=1$ Thus $p$ is maximum, so $x=0$ is a closed end At $x=2 m \cos \frac{3 \pi x}{2}=\cos \frac{3 \pi \times 2}{2}=-1$ Thus $|p|$ is maximum at $x=2 m,$ so $x=2$ is also a closed end. Hence the given organ pipe is closed at both ends and length of the pipe is $2 m$

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

In an organ pipe whose one end is at $x = 0$, the pressure is expressed by $p = {p_0}\cos \frac{{3\pi x}}{2} \,\,sin\,\, 300\pi t$ where $x$ is in meter and $t$ in $sec$. The organ pipe can be

Aclosed at one end, open at another with length $= 0.5m$
Bopen at both ends, length $= 1m$
Cclosed at both ends, length $= 2m$
Dclosed at one end, open at another with length = $\frac{2}{3} m$

Advanced

STD 11 Science
NEET
STD 11 - 14. waves and sound
Physics

Download our app
and get started for free

Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*

Download App

Download our appand get started for free

Similar Questions

Download our app
and get started for free