MCQ
In Bohr’s model, atomic radius of the first orbit is $\gamma $, the radius of the $3^{rd}$ orbit, is
- A$\gamma /3$
- B$\gamma $
- C$3\gamma $
- ✓$9\gamma $
For $I^{st}$ orbit $\gamma = 1$
For $III^{rd}$ orbit = $\gamma \propto {3^2} = 9$
So it will 9$\gamma $.
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