MCQ
In $CuS{O_4}$ solution when electric current equal to $2.5$ faraday is passed, the gm equivalent deposited on the cathode is
- A$1$
- B$1.5$
- C$2$
- ✓$2.5$
✓
Answer
Correct option: D.
$2.5$
d
(d) Since $1$ faraday deposits $1\, gm$ equivalent.
(d) Since $1$ faraday deposits $1\, gm$ equivalent.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
$4$ -Pentenoic acid when treated with $I_2$ and $NaHCO_3$ gives
→The major product of the given reaction is
→ $[Figure]$ $\xrightarrow[{(ii)\,{H_2}S{O_4}\,,\,heat}]{{(i)\,OHCC{H_2}COCl}}$
When copper is heated with conc. $HNO_3$ it produces
→What are the suitable reagent for following conversion:
Value of $CFSE$, in tetrahedral complex having $3d^4$ configuration of metal ion, surrounded by strong field ligands, will be
→IUPAC name of the following compound
The highest electrical conductivity of the following aqueous solutions is of
$Xe{F_4}$ Processing strongly with water gives .......
→Two $5$ molal solutions are prepared by dissolving a non-electrolyte, non-volatile solute separately in the solvents $X$ and $Y$. The molecular weights of the solvents are $M_X$ and $M_Y$, respectively where $M_X\, = \frac{3}{4} M_Y$. The relative lowering of vapour pressure of the solution in $X$ is $''m''$ times that of the solution in $Y$. Given that the number of moles of solute is very small in comparison to that of solvent, the value of $''m''$ is
→Transition metals are not characterized by