Question
In ∆ABC, C = 56° C = 56° ∠B = ∠C and ∠A = 100° ; find ∠B.
✓
Answer
∠A + ∠B + ∠C = 180°
⇒ 100° + ∠B + ∠B = 180°
⇒ 2∠B = 180° 100°
$\angle B=\frac{80^{\circ}}{2}$
∠B = 40°
∠C = ∠B = 40°
⇒ 100° + ∠B + ∠B = 180°
⇒ 2∠B = 180° 100°
$\angle B=\frac{80^{\circ}}{2}$
∠B = 40°
∠C = ∠B = 40°
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