Experimental values, At $STP.$
$V_{1}=40 \,\mathrm{mL}$
$V_{2}=?$
$T_{1}=300 \,\mathrm{K}$
$T_{2}=273 \,\mathrm{K}$
$P_{1}^{2}=725-25=700\, \mathrm{mm}$
$P_{2}=760\, \mathrm{mm}$
$\frac{P_{1} V_{1}}{T_{1}}=\frac{P_{2} V_{2}}{T_{2}}$
$V_{2}=\frac{P_{1} V_{1} T_{2}}{T_{1} P_{2}}=\frac{700 \times 40 \times 273}{300 \times 760}=33.52\, \mathrm{mL}$
$22400\, \mathrm{mL}$ of $\mathrm{N}_{2}$ at $STP$ weighs $=28\, \mathrm{g}$
$\therefore 33.52\, \mathrm{mL}$ of $\mathrm{N}_{2}$ at $STP$ weighs $=\frac{28 \times 33.52}{22400}$
$=0.0419\; \mathrm{g}$
$\%$ of $\mathrm{N}=\frac{\text { Mass of nitrogen at STP }}{\text { Mass of organic compound taken }} \times 100$
$=\frac{0.0419}{0.25} \times 100=16.76 \%$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
