Question
In Fig. a rectangle with perimeter $264\ cm$ is divided into five congruent rectangles. Find the perimeter of one of the rectangles.
✓
Answer
Let $l$ and $b$ be the length and breadth of each reatangle, respectively.
Given, perimeter of a rectangle $= 264\ cm$
According to the figure, $4l + 5b = 264$ And $2l = 3b$
Put the value of $3b$ from Eq.$(ii)$ in Eq.$(i), 2(2l) + 5b = 264$
$\Rightarrow 2 \times 3\text{b} + 5\text{b} = 264$
$\Rightarrow 6\text{b} + 5\text{b} = 264$
$\Rightarrow11\text{b}=264\Rightarrow\text{b}=\frac{264}{11}$
$\Rightarrow \text{b}= 24\text{cm}$
$\therefore\text{l}=\frac{3\text{b}}{2}=\frac{3\times24}{2}=36\text{cm}$
Hence, perimeter of the rectangle $= 2(l + b) = 2(36 + 24) =12\ cm$
Given, perimeter of a rectangle $= 264\ cm$
According to the figure, $4l + 5b = 264$ And $2l = 3b$
Put the value of $3b$ from Eq.$(ii)$ in Eq.$(i), 2(2l) + 5b = 264$
$\Rightarrow 2 \times 3\text{b} + 5\text{b} = 264$
$\Rightarrow 6\text{b} + 5\text{b} = 264$
$\Rightarrow11\text{b}=264\Rightarrow\text{b}=\frac{264}{11}$
$\Rightarrow \text{b}= 24\text{cm}$
$\therefore\text{l}=\frac{3\text{b}}{2}=\frac{3\times24}{2}=36\text{cm}$
Hence, perimeter of the rectangle $= 2(l + b) = 2(36 + 24) =12\ cm$
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