Question
In Fig., $\text{DEFG}$ is a square in a triangle $\text{ABC}$ right angled at $A$ . Prove that
$i. \triangle AGF \sim \triangle DBG$
$ii. \triangle AGF \sim \triangle EFC$

$i. \triangle AGF \sim \triangle DBG$
$ii. \triangle AGF \sim \triangle EFC$

