MCQ
- A37º
- B43º
- C45º
- D47º
✓
Answer
- 47º
Solution:
Let if l1 || l2 and AB is tranverse to it.
Then,
$\angle\text{PBA}$ should be equal $\angle\text{BAS}$ (Alternate angles)
So if l1 || l2, then $\angle\text{BAS}=70^\circ$
$\Rightarrow\angle\text{BAC}=78^\circ-35^\circ=43^\circ\dots(1)$
Now, in $\triangle\text{ABC}$
$\text{x}^\circ+\angle\text{C}+\angle\text{BAC}=180^\circ$
$\Rightarrow\text{x}^\circ+90^\circ+43^\circ=180^\circ$
$\Rightarrow\text{x}^\circ=180^\circ-90^\circ-43^\circ=47^\circ$
$\Rightarrow\text{x}^\circ=47^\circ$
So if xº = 47º then l1 || l2
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