(c) $70^{\circ}$ In $\triangle A B D$, we have $\begin{array}{l}\angle D A B=60^{\circ} \text { and } \angle A B D=50^{\circ} \\ \angle A D B=180^{\circ}-60^{\circ}-50^{\circ}=70^{\circ}\end{array}$ We find that $\angle A D B$ and $\angle A C B$ are angles made by the are $A B$ in the same segment. $ ∴\quad$ \angle A C B=\angle A D B \Rightarrow \angle A C B=70^{\circ}$
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