Question
In Fig. it is given that $\text{AB}=\text{CD}$ and $\text{AD}=\text{BC}.$ Prove that $\triangle\text{ADC}\cong\triangle\text{CBA}.$
✓
Answer
In $\triangle\text{ADC}$ and $\triangle\text{CBA}$$\text{AB}=\text{CD}$ (given)
$\text{AC}=\text{AC}$ (common)
$\text{AD}=\text{BC}$ (given)
By SSS congurence criterion $\triangle\text{ADC}\cong\triangle\text{CBA}$
$\text{AC}=\text{AC}$ (common)
$\text{AD}=\text{BC}$ (given)
By SSS congurence criterion $\triangle\text{ADC}\cong\triangle\text{CBA}$
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