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Lines and Angles — Maths STD 9 — Question

Gujarat BoardEnglish MediumSTD 9MathsLines and Angles1 Mark
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Answer

  1. 20º
    Solution:
    Let,
    AB, CD and EF intersect at O
    $\angle\text{COB}=\angle\text{AOD}$ (Vertically opposite angle)
    $\angle\text{AOD}=3\text{x}+10\text{ (i)}$
    $\angle\text{AOE}+\angle\text{AOD}+\angle\text{DOF}=180^\circ$ (Linear pair)
    x + 3x + 10º + 90º = 180º
    4x + 100º = 180º
    4x = 80º
    x = 20º.

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