Question
In figure for vernier callipers, calculate the length recorded.
✓
Answer
$
\begin{array}{l}
\text { Main scale divisions of vernier callipers in one centimetre }=10\\
\begin{array}{l}
\begin{aligned}
\text { Pitch } & =\frac{\text { Unit of main scale }}{\text { Number of divisions in the unit }} \\
& =\frac{1}{10} cm=0.1 cm
\end{aligned} \\
\text { Least count (L.C.) }=\frac{\text { Pitch }}{\text { No. of divisions on the vernier scale }} \\
\qquad \text { L.C. }=\frac{0.1}{10} cm=0.01 cm \\
\text { Here main scale reading }=7.3 cm \\
\text { Vernier scale reading (V.S.D.) coinciding with main scale }=5 \text { th } \\
\text { Length recorded }=\text { Main scale reading }+ \text { L.C. } \times \text { V.S.D. } \\
\quad=7.3+0.01 \times 5=7.3+0.05=7.35 cm
\end{array}
\end{array}
$
\begin{array}{l}
\text { Main scale divisions of vernier callipers in one centimetre }=10\\
\begin{array}{l}
\begin{aligned}
\text { Pitch } & =\frac{\text { Unit of main scale }}{\text { Number of divisions in the unit }} \\
& =\frac{1}{10} cm=0.1 cm
\end{aligned} \\
\text { Least count (L.C.) }=\frac{\text { Pitch }}{\text { No. of divisions on the vernier scale }} \\
\qquad \text { L.C. }=\frac{0.1}{10} cm=0.01 cm \\
\text { Here main scale reading }=7.3 cm \\
\text { Vernier scale reading (V.S.D.) coinciding with main scale }=5 \text { th } \\
\text { Length recorded }=\text { Main scale reading }+ \text { L.C. } \times \text { V.S.D. } \\
\quad=7.3+0.01 \times 5=7.3+0.05=7.35 cm
\end{array}
\end{array}
$
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