MCQ
In figure, if $\angle\text{AOB}=125^\circ,$ then $\angle\text{COD}$ is equal to :
- A$62.5^\circ$
- B$45^\circ$
- C$35^\circ$
- ✓$55^\circ$
✓
Answer
Correct option: D.
$55^\circ$
we know that, the opposite sides of a quadrilateral circumscribing a circle subtend supplementary angles at the centre of the circle.
i.e., $\angle\text{AOB}+\angle\text{COD}=180^\circ$
$\Rightarrow\ \angle\text{COD}=180^\circ-\angle\text{AOB}$
$=180^\circ - 125^\circ = 55^\circ$
i.e., $\angle\text{AOB}+\angle\text{COD}=180^\circ$
$\Rightarrow\ \angle\text{COD}=180^\circ-\angle\text{AOB}$
$=180^\circ - 125^\circ = 55^\circ$
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