MCQ
In graphical solutions of linear inequalities, solution can be divided into.
  • A
    One subset
  • Two subsets
  • C
    Three subsets
  • D
    Four subsets

Answer

Correct option: B.
Two subsets
In graphical solutions of linear inequalities, solution can be divided into two subsets.
for example, $2\text{x}+\text{y}\leq4$
One subset includes all values (x, y) that satisfy the equation 2x + y = 4 and the other subset includes all the values (x, y) that satisfy 2x + y < 4.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

The length of the perpendicular drawn from the point $(4, -7, 3)$ on the $y-$axis is:
The value of the determinant $\left| {\,\begin{array}{*{20}{c}}1&1&1\\{b + c}&{c + a}&{a + b}\\{b + c - a}&{c + a - b}&{a + b - c}\end{array}\,} \right|$ is
Choose the correct answer from the given four options.If matrix $A = [a_{ij}]_{2\times 2},$ where $a_{ij} = 1,$ if $\text{i}\neq\text{j}$ and $0$ if $i = j$ then $A^2$ equal to:
If $\text{f(x)}=\begin{cases}\frac{1-\cos10\text{x}}{\text{x}^2},&\text{x}<0\\\text{a},&\text{x}=0\\\frac{\sqrt{\text{x}}}{\sqrt{625+\sqrt{\text{x}}}-25},&\text{x}>0\end{cases}$ then the value of so that f(x) may be continuous at x = 0 is:
Let $\vec{a}=\alpha \hat{i}+\hat{j}-\hat{k}$ and $\vec{b}=2 \hat{i}+\hat{j}-\alpha \hat{k}, \alpha>0$. If the projection of $\vec{a} \times \vec{b}$ on the vector $-\hat{i}+2 \hat{j}-2 \hat{k}$ is $30 ,$ then $\alpha$ is equal to
A square matrix $A$ has $9$ elements. What is the possible order of $A\ ?$
If $\vec{\text{a}}$ be the position vector whose tip is $(5, -3)$ find the coordinates of a point $B$ such that $\vec{\text{AB}}=\vec{\text{a}}$ the coordinates of $A$ being $(4, -1):$
If $A = \left[ {\begin{array}{*{20}{c}}2&2\\a&b\end{array}} \right]$ and ${A^2} = O$, then $(a,b) = $
The vectors $a, b$ and $c$ are of the same length and taken pairwise, they form equal angles. If $a = i + j$ and $b = j + k,$ then the co-ordinates of $c$ are
Let A = {2, 3, 4, 5, ..., 17, 18}. Let $'\simeq'$ be the equivalence relation on A × A, cartesian product of A with itself, defined by $(\text{a, b})\simeq(\text{c, d)}$ if ad = bc. Then, the number of ordered pairs of the equivalence class of (3, 2) is: