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In $H_2–O_2$ fuel cell, the reaction taking place at negative electrode is :

• ✓
  $2 H _{2( g )}+4 OH _{( aq )}^{-} \longrightarrow 4 H _2 O _{( l )}+4 e ^{-}$
• B
  $2 H _{2( g )}+2 OH _{( aq )}^{-} \longrightarrow 2 H _2 O _{( l )}+2 e ^{-}$
• C
  $O _{2( g )}+2 H _2 O _{( l )} \longrightarrow 4 OH _{( aq )}^{-}$
• D
  $4 OH _{( aq )}^{-} \longrightarrow O _{2( g )}+2 H _2 O _{( l )}+4 e ^{-}$