In hydrogen atom, the electron is making $6.6 \times {10^{15}}\,rev/\sec $ around the nucleus in an orbit of radius $0.528\, \mathop A\limits^o $. The magnetic moment $(A - {m^2})$ will be
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(c) $i = 6.6 \times {10^{15}} \times 1.6 \times {10^{ - 19}} = 10.5 \times {10^{ - 4}}\,amp$
$A = \pi {R^2} = 3.142 \times {\left( {0.528} \right)^2} \times {10^{ - 20}}\,{m^2}$
$==>$ $M = iA = 10.5 \times {10^{ - 4}} \times 3.142 \times {\left( {0.528} \right)^2} \times {10^{ - 20}}$
$ = 10 \times {10^{ - 24}}\,units = 1 \times {10^{ - 23}}\,units$
$A = \pi {R^2} = 3.142 \times {\left( {0.528} \right)^2} \times {10^{ - 20}}\,{m^2}$
$==>$ $M = iA = 10.5 \times {10^{ - 4}} \times 3.142 \times {\left( {0.528} \right)^2} \times {10^{ - 20}}$
$ = 10 \times {10^{ - 24}}\,units = 1 \times {10^{ - 23}}\,units$
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