MCQ
In ${K_4}Fe{\left( {CN} \right)_6},$ $Fe$ is in the form of
- AAn atom
- BAn ion
- CCationic complex
- ✓Anionic complex
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$[A]$ $4$-methylchlorobenzene $[B]$ $4$-chlorotoluene $[C]$ $1$-chloro-$4$-methylbenzene $[D]$ $1$-methyl-$4$-chlorobenzene
| LIST-I Name reaction | LIST-II Product obtainable | ||
| A. | Swarts reaction | I. | Ethyl benzene |
| B. | Sandmeyer's reaction | II. | Ethyl iodide |
| C. | Wurtz Fittig reaction | III. | Cyanobenzene |
| D. | Finkelstein reaction | IV. | Ethyl fluoride |


Statement-$I$: Since fluorine is more electronegative than nitrogen, the net dipole moment of $\mathrm{NF}_3$ is greater than $\mathrm{NH}_3$.
Statement-$II$: In $\mathrm{NH}_3$, the orbital dipole due to lone pair and the dipole moment of $\mathrm{NH}$ bonds are in opposite direction, but in $\mathrm{NF}_3$ the orbital dipole due to lone pair and dipole moments of $N-F$ bonds are in same direction. In the light of the above statements. Choose the most appropriate from the options given below.