MCQ
In ${K_4}Fe{\left( {CN} \right)_6},$ $Fe$ is in the form of
  • A
    An atom
  • B
    An ion
  • C
    Cationic complex
  • Anionic complex

Answer

Correct option: D.
Anionic complex
d
(d) ${K_4}[Fe\,{(CN)_6}] \to 4{K^ + } + {[Fe\,{(CN)_6}]^{4 - }}$
Complex has negative charge so it is anionic complex.

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