MCQ
In $\left[ {Cu\,{{\left( {N{H_3}} \right)}_4}} \right]\,S{O_4},\,\,;\,Cu$ has following hybridization
- ✓$ds{p^2}$
- B$s{p^3}$
- C$s{p^2}$
- D$s{p^3}{d^2}$
✓
Answer
Correct option: A.
$ds{p^2}$
a
The hybridization should be $dsp^2.$
The hybridization should be $dsp^2.$
The $Cu$ atom is in form of $Cu ^{+2}$ in the compound.
In $Cu ^{+2}$, the electronic configuration would be $1 s^2 \,2 s^2 \,2 p^6\, 3 s^2\, 3 p^6 \,3 d^9 \,4 s^0$
So, there would be a rearrangement of electrons in $Cu ^{2+}$ because of the $NH _3$ ligand (which is a strong one). And the last electron in the $d$-orbital would be out waiting for the $N'$s electrons to fill up first.
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