$\sigma = \frac{{Iateral\,strain\left( \beta \right)}}{{longitudinal\,strain\left( \alpha \right)}}$
For material like copper, $\sigma = 0.33$
$And,\,y = 3k\left( {1 - 2\sigma } \right)$
$Also,\frac{9}{y} = \frac{1}{k} + \frac{3}{n}$
$y = 2n\left( {1 + \sigma } \right)$
$Hence,n < y < k$
Assertion $(A)$:The stretching of a spring is determined by the shear modulus of the material of the spring.
Reason $(R)$:A coil spring of copper has more tensile strength than a steel spring of same dimensions.
In the light of the above statements, choose the most appropriate answer from the options given below:
