In NaOH solution [ OH ^ - ]is 2.87 10^ -4 . Calculate the pH of s… - Vidyadip

Question

In NaOH solution $\left[ OH ^{-}\right]$is $2.87 \times 10^{-4}$. Calculate the pH of solution.

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Answer

$\text { Given : }\left[ OH ^{-}\right]=2.87 \times 10^{-4} M , pH =?$
$pOH =-\log _{10}\left[ OH ^{-}\right]$
$=-\log _{10} 2.87 \times 10^{-4}$
$=-(\overline{4} .4579)$
$=(4-0.4579)$
$=3.5421$
$\because pH + pOH =14$
$\therefore pH =14- pOH =14-3.5421=10.4579$
$pH =10.4579 .$

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