MCQ
In order that the function $f (x)=(x+1)^{\frac{1}{x}}$ is continuous at $x=0, f (0)$ must be defined as
  • A
    $f(0)=0$
  • $f(0)=e$
  • C
    $f(0)=\frac{1}{e}$
  • D
    $f(0)=1$

Answer

Correct option: B.
$f(0)=e$
(B)
For $f (x)$ to be continuous at $x=0$,
$f (0)=\lim _{x \rightarrow 0} f (x)=\lim _{x \rightarrow 0}(1+x)^{\frac{1}{x}}= e$

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