Question
In Quadrilateral ABCD, $\angle\text{A} = 110^\circ, \ \angle\text{B} = 75^\circ$ and $\angle\text{C} = 35^\circ.$ Find $\angle\text{D}=\ ?$
✓
Answer
- 140º
Solution:
$\angle\text{A} + \angle\text{B} + \angle\text{C} + \angle\text{D} = 360^\circ$ (angle sum property of quadrilateral).
$110 + 75^\circ + 35^\circ + \angle\text{D} = 360^\circ$
$\angle\text{D} = 360^\circ - 220^\circ = 140^\circ$
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