Question
In quadrilateral ABCD, if $\angle\text{A}= 60^\circ$ and $\angle\text{B}: \angle\text{C}: \angle\text{D} = 2:3:7,$ then $\angle\text{D}$ is:
✓
Answer
- 175º
Solution:
In quadrilateral, the sum of the all four angles equal to 360º.
Let $\angle\text{B} = 2\text{x}, \ \angle\text{C} = 3\text{x}$ and $\angle\text{D} = 7\text{x}.$
$\angle\text{A} + \angle\text{B} + \angle\text{C} + \angle\text{D} = 360^\circ$
60 + 2x + 3x + 7x = 360
12x = 300
x = 25
So, $\angle\text{D} = 7\text{x} = 7 (25) = 175^\circ$
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