In simple harmonic motion, the total mechanical energy of given system is E. If mass of oscillating particle $P$ is doubled then the new energy of the system for same amplitude is:
A $\frac{E}{\sqrt{2}}$
B$\mathrm{E}$
C$\mathrm{E} \sqrt{2}$
D$2 \mathrm{E}$
JEE MAIN 2024, Diffcult
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B$\mathrm{E}$
b $\text { T.E. }=\frac{1}{2} \mathrm{kA}^2$
since $A$ is same $T.E.$ will be same correct option $(2)$
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