Question
In $\square \mathrm{PQRS}$, side $\mathrm{PS} \|$ side $\mathrm{QR}$ and side $\mathrm{PQ} \cong$ side $\mathrm{SR}$, side $\mathrm{QR}>$ side $\mathrm{PS}$ then prove that $\angle \mathrm{PQR} \cong \angle \mathrm{SRQ}$
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