MCQ
In the above reaction product is


- A${C_2}{H_5}O{C_2}{H_5}$
- ✓${C_6}{H_5}O{C_2}{H_5}$
- C${C_6}{H_5}O{C_6}{H_5}$
- D${C_6}{H_5}I$


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$[Figure]$ $\xrightarrow[{(ii){H_2}O}]{{(i)\,{C_2}{H_5}MgBr}}A\xrightarrow{{HCl}}B$
If $E_{op}^o$ for this electrode is $1.30\,volt$ then what will be the oxidation electrode potential at $pH = 3$ ? .............. $\mathrm{volt}$