If $E_{op}^o$ for this electrode is $1.30\,volt$ then what will be the oxidation electrode potential at $pH = 3$ ? .............. $\mathrm{volt}$
${{\text{E}}_{op}}=\text{E}_{o\text{p}}^{o}-0.059\,\,{{\log }_{10\,}}\left[ {{\text{H}}^{+}} \right]$
$=\text{E}_{\text{op}}^{o}+0.059\times \text{pH}$
${=1.3+0.059 \times 3}$
${=1.33+0.177}$
${=1.477}$
${=1.48\, \mathrm{Volt}}$
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