MCQ
In the above reaction, the reagent $"A"$ is :


- A$NaBH _{4}, H _{3} O ^{+}$
- B$\operatorname{LiAlH}_{4}$
- ✓Alkaline $KMnO _{4}, H ^{+}$
- D$HCl , Zn - Hg$


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Which forms di-iodide on reaction with $HI $ (excess) ?