MCQ
In the adjoining figure, $AB = AC$ and $\angle\text{A} = 70^\circ,$ then $\angle\text{C}$ is:
- A$40^\circ$
- ✓$55^\circ$
- C$110^\circ$
- D$70^\circ$
✓
Answer
Correct option: B.
$55^\circ$
Since, It is given that $AB = AC,$ then $\angle\text{B}=\angle\text{C}$ (Isosceles triangle property)
Given $\angle\text{A}=70^\circ$ Let angle $B$ and $C$ be $x^\circ .$
Sum of all the three angles of triangle $= 180^\circ $, therefore $\angle\text{A}+\angle\text{B}+\angle\text{C}=180^\circ$
$70 + x + x = 180^\circ$
$x = 55^\circ$
$\angle\text{C}=55^\circ$
Given $\angle\text{A}=70^\circ$ Let angle $B$ and $C$ be $x^\circ .$
Sum of all the three angles of triangle $= 180^\circ $, therefore $\angle\text{A}+\angle\text{B}+\angle\text{C}=180^\circ$
$70 + x + x = 180^\circ$
$x = 55^\circ$
$\angle\text{C}=55^\circ$
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