MCQ
In the adjoining figure, $AB = BC$ and $\angle ABD =\angle CBD$, then another angle which measures $30^{\circ}$ is
- A$\angle BCA$
- B$\angle BCD$
- C$\angle BDA$
- D$\angle BAD$
✓
Answer
(c) $\angle BDA$
Explanation: In triangle ABD and CBD
$AB = BC$ and $\angle ABD =\angle CBD$ (Given)
BD (Common)
Therefore In triangle ABD and CBD are congruent by SAS criteria.
Therefore, $\angle BDA =30^{\circ}$ (by CPCT)
Explanation: In triangle ABD and CBD
$AB = BC$ and $\angle ABD =\angle CBD$ (Given)
BD (Common)
Therefore In triangle ABD and CBD are congruent by SAS criteria.
Therefore, $\angle BDA =30^{\circ}$ (by CPCT)
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