Question
In the adjoining figure, ABCD is a parallelogram in which $\angle BAD =70^{\circ}$ and $\angle CBD =50^{\circ}$.
Calculate : (i) $\angle ADB$
(ii) $\angle CDB$.
Image

Answer

(i) $\angle ADB =50^{\circ}$
(ii) $\angle CDB =60^{\circ}$

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