In the adjoining figure, four capacitors are shown with their respective capacities and the $P.D.$ applied. The charge and the $P.D.$ across the $4\,\mu F$ capacitor will be
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(d) Total capacitance $\frac{1}{C} = \frac{1}{{20}} + \frac{1}{8} + \frac{1}{{12}}$ $==>$ $C = \frac{{120}}{{31}}\,\mu F$
Total charge $Q = CV = \frac{{120}}{{31}} \times 300 = 1161\,\mu C$
Charge, through $4 \,µF$ condenser $ = \frac{{1161}}{2} = 580\,\mu C$
and potential difference across it $ = \frac{{580}}{4} = 145\,V$
Total charge $Q = CV = \frac{{120}}{{31}} \times 300 = 1161\,\mu C$
Charge, through $4 \,µF$ condenser $ = \frac{{1161}}{2} = 580\,\mu C$
and potential difference across it $ = \frac{{580}}{4} = 145\,V$
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