MCQ
In the adjoining figure, the rule by which $\triangle\text{ABC}\cong\triangle\text{ADC}.$
- ✓$SSS$
- B$AAS$
- C$SAS$
- D$RHS$
✓
Answer
Correct option: A.
$SSS$
an $\triangle\text{ABC} $ and $\triangle\text{ADC}, $ we have$AB = AD (4\ cm)$
$BC = DC (2.7\ cm)$
$AC = AC$ (commom in both)
Hence, $\triangle\text{ABC}\cong\triangle\text{ADC}$ by $SSS$ criterion.
$BC = DC (2.7\ cm)$
$AC = AC$ (commom in both)
Hence, $\triangle\text{ABC}\cong\triangle\text{ADC}$ by $SSS$ criterion.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
$(x + 1)$ is a factor of $x^n +1 $ only if.
→The Diagonals $AC$ and $BO$ of a Parallelogram $ABCD$ intersect each other at the point $O$ such that $\angle\text{DAC} = 30^\circ$ and $\angle\text{AOB} = 70^\circ.$ Then $\angle\text{DBC}?$
→If the sides of a triangle are doubled, then its area:
In the given figure, $O$ is the centre of a circle. If $\angle\text{AOB}=100^\circ$ and $\angle\text{AOC}=90^\circ,$ then $\angle\text{BAC}=?$
→An exterior angle of a triangle is $110^\circ $ and its two interior opposite angles are equal. Each of these equal angles is:
→If all the three angles of a triangle are equal, then each one of them is equal to:
$\frac{1}{\sqrt9-\sqrt8}$ is equal to:
→The sides of a triangle are $7\ cm, 9\ cm$ and $14\ cm.$ Its area is:
→The volume of a cube whose diagonal is $8\sqrt{3}\text{cm}$ is:
→If two supplementary angles are in the ratio $2 : 7$, then the angles are:
→