MCQ
- A80º
- B60º
- C30º
- D50º
✓
Answer
- 50º
Solution:
In triangle ABC, $\angle\text{BAC} = 30^\circ$ and $\angle\text{ABC} = 100^\circ$ (Given)
$\angle\text{BAC} + \angle\text{ABC} + \angle\text{BCA} = 180^\circ$
$\angle\text{BAC} = 50^\circ$
Also $\angle\text{ACD} = 50^\circ$ (Since, $\triangle\text{ABC}\cong\triangle\text{ADC}$)
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Write the correct answer in the following:
The number of dimensions, a solid has:
The number of dimensions, a solid has:
- 1
- 2
- 3
- 0
In a $\triangle\text{ABC},\angle\text{A}=50^\circ$ and BC is produced to a point D. If the bisectors of $\angle\text{ABC}$ and $\angle\text{ACD}$ meet at E, then $\angle\text{E}=$
→→
In a bar graph, the height of a bar is 5 cm and it represents 40 units. The height of the bar representing 56 units is
93 + (-3)3 - 63 = ?
- 432
- 270
- 486
- 540
If the TSA of a solid cylinder is $200\pi\text{ sq .cm}$ and its radius is 5cm then the sum of its height and radius is:
→The height h of a cylinder equals the circumference of the cylinder. In terms of h what is the volume of the cylinder?
→- $\frac{\text{h}^3}{4\pi}$
- $\frac{\text{h}^2}{2\pi}$
- $\frac {\text{h}^3}{2}$
- $\pi\text{h}^3$
In $\triangle\text{ABC, }\angle\text{A}=40^{\circ}$ and $\angle\text{B}=60^{\circ}.$ Then the longest side of $\triangle\text{ABC}$ is:
→Which of the following is a rational number?
→- $\sqrt{2}$
- $\sqrt{23}$
- $\sqrt{225}$
- $0.1010010001...$
The value of (xa-b)a+b × (xb-c)b+c × (xc-a)c+a is: