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AreaAreas of Parallelograms and Triangles — Maths STD 9 — Question

Gujarat BoardEnglish MediumSTD 9MathsAreaAreas of Parallelograms and Triangles2 Marks
Question
In the adjoining figure, $\triangle\text{ABC}$ and $\triangle\text{DBC}$ are on the same base $BC$ with $A$ and $D$ on opposite sides of $BC$ such that $\text{ar}(\triangle\text{ABC})=\text{ar}(\triangle\text{DBC}).$ Show that $BC$ bisects $AD.$
✓

Answer

Given: Two triangle, $\text{i.e.}\triangle\text{ABC}$ and $\triangle\text{DBC}$ which have same base $BC$ and point $A$ and $D$ lie on opposite sides of $BC$ and $\text{ar}(\triangle\text{ABC})=\text{ar}(\triangle\text{DBC}).$

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