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Areas of Parallelograms and Triangles — Maths STD 9 — Question

Maharashtra BoardEnglish MediumSTD 9MathsAreas of Parallelograms and Triangles2 Marks
Question
In the adjoining figure, $\triangle\text{ABC}$ and $\triangle\text{DBC}$ are on the same base BC with A and D on opposite sides of BC such that $\text{ar}(\triangle\text{ABC})=\text{ar}(\triangle\text{DBC}).$
Show that BC bisects AD.
✓

Answer

Given:
Two triangle, $\text{i.e.}\triangle\text{ABC}$ and $\triangle\text{DBC}$ which have same base BC and point A
and D lie on opposite sides of BC and $\text{ar}(\triangle\text{ABC})=\text{ar}(\triangle\text{DBC}).$

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