Question
Simplify the following:$\frac{6(8)^{\text{n}+1}+16(2)^{3\text{n}-2}}{10(2)^{3\text{n}+1}-7(8)^\text{n}}$
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Answer
$\frac{(6\times8^{\text{n}+1})+(16\times2^{3\text{n}-2})^{}}{(10\times2^{3\text{n}+1})-7\times(8)^{\text{n}}}$$=\frac{(6\times8^\text{n}\times8)+(16\times8^\text{n}\times\frac{1}{4})}{(10\times8^\text{n}\times2)-7\times(8)^\text{n}}$
$=\frac{8^\text{n}(48+4)}{8^\text{n}(20-7)}$
$=\frac{52}{13}=4$
$=\frac{8^\text{n}(48+4)}{8^\text{n}(20-7)}$
$=\frac{52}{13}=4$
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