Question

In the AP, –4, ?, ?, ?, ?, 6 find the missing terms?

Answer

Let the common difference of the given AP be d.
a = -4
6th term = 6
$ \Rightarrow $ -4 + (6 - 1)d = 6 $\because {a_n} = a + \left| {a - 1} \right|d$
$ \Rightarrow $ -4 + 5d = 6
$ \Rightarrow $ 5d = 6 + 4
$ \Rightarrow $ 5d = 10
$ \Rightarrow d = \frac{{10}}{5}$
$ \Rightarrow $ d = 2
Therefore,
Second term = -4 + 2 = -2
Third term = -2 + 2 = 0
Fourth term = 0 + 2 = 2
Fifth term = 2 + 2 = 4
Hence, the missing terms are -2, 0, 2, 4

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