MCQ
In the chemical reaction $C{l_2} + {H_2}S \to 2HCl + S$, the oxidation number of sulphur changes from
- A$0$ to $2$
- B$2$ to $ 0$
- ✓$-2 $ to $ 0$
- D$-2$ to $ -1$
✓
Answer
Correct option: C.
$-2 $ to $ 0$
(c) Oxidation state of sulphur in ${H_2}S$ is $-2,$ while it is zero in $‘S’$ i.e. in this reaction oxidation of sulphur and reduction of chlorine is takes place.
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